The number of terms in the finite A.P. 13, 26 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given sequence is an arithmetic progression $(A.P.)$ where the first term $a = 13$.The common difference $d = 26 - 13 = 13$.The last term $T_n

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(C) The given sequence is an arithmetic progression $(A.P.)$ where the first term $a = 13$.The common difference $d = 26 - 13 = 13$.The last term $T_n = 650$.The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n - 1)d$.Substituting the values: $650 = 13 + (n - 1)13$.Dividing the entire equation by $13$: $50 = 1 + (n - 1)$.$50 = n$,so $n = 50$.Therefore,the number of terms in the $A.P.$ is $50$.

The number of terms in the finite $A.P.$ $13, 26, 39, \ldots, 650$ is ........

Similar Questions

Find the $16^{th}$ term and the $n^{th}$ term of the $A.P.$ $9, 12, 15, \ldots$

The $10^{\text{th}}$ term of the $AP: 5, 8, 11, 14, \ldots$ is

If $7$ times the $7^{\text{th}}$ term of an $AP$ is equal to $11$ times its $11^{\text{th}}$ term,then its $18^{\text{th}}$ term will be

Which term of the $A.P.$ $34, 27, 20, 13, \ldots$ is $-519$ (in $^{th}$)?

Find the $n^{th}$ term of the $A.P. \, 18, 16.5, 15, 13.5, \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module